New Serial DOPAIR2
When we work out
969 int last_pj = count_j - 1; 970 while (sort_j[last_pj].d > di && last_pj > 0) last_pj--;
is it not quicker to start from 0 and move outwards instead starting at the edge and working our way in? e.g.
int last_pj = 0; while (sort_j[last_pj].d < di && last_pj < count_j) last_pj++;
The same applies for
To upload designs, you'll need to enable LFS and have an admin enable hashed storage. More information